SOLUTION: Solving 6x^2+3x-18=0,using quadratic formula. would that be ax^+bx+c=0.

Question 140923: Solving 6x^2+3x-18=0,using quadratic formula. would that be ax^+bx+c=0.
Found 2 solutions by checkley77, stanbon:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
6x^2+3x-18=0
Following is the quadratic formula:

x=(-3+-sqrt[3^2-4*6*-18])/2*6
x=(9+-sqrt[9+432])/12
x=(9+-sqrt441)/12
x=(9+-21)/12
x=(3+21)/12
x=24/12
x=2 answer.
x=(3-21)/12
x=-18/12
x=-1.5 answer.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
6x^2+3x-18=0,using quadratic formula
----------------------
Formula:
x = [-b +- sqrt(b^2-4ac)]/(2a)
-------------------
Your problem:
x = [-3 +- sqrt(9-4*6*-18)]/12
x = [-3 +- sqrt(441)]/12
x = [-3 +- 21]/12
x = (-3+21)/12 or x = (-3-21)/12
x =(3/2) or x = -2
========================
Cheers,
Stan H.
RELATED QUESTIONS
Please help! Solve by using quadratic formula {{{ ax^2+bx+c=0 }}}. {{{ 6x^2-2x-1=0... (answered by jim_thompson5910)
This question deals with solving the quadratic equation by using the quadratic formula.... (answered by scott8148)
Please help! Solve by using quadratic formula {{{ ax^2+bx+c=0 }}}. {{{ x^2-3x-1=0... (answered by jim_thompson5910)
Begin with ax^2 + bx + c = 0 and derive the quadratic formula by completing the square (answered by funmath)
Solve 6x^2+3x-18=0 using the quadratic... (answered by oscargut,jim_thompson5910)
Use the quadratic equation to solve 6x^2+x=0. I know I have to use ax^2+bx+c=0. What... (answered by Alan3354)
Please help! Solve by using quadratic formula {{{ ax^2+bx+c=0 }}}. {{{ 4x^2+x-1=0... (answered by jim_thompson5910)
solve the quadratic equation 6x^2 +3x -18=0 using the quadratic... (answered by unlockmath)
Solve 3x^2-6x+1=0 using the quadratic... (answered by richwmiller)