SOLUTION: solve equation using imaginary and complex numbers x^2+4x+24=0 please help! =)

Question 140640: solve equation using imaginary and complex numbers x^2+4x+24=0
please help! =)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let's use the quadratic formula to solve for x:

Starting with the general quadratic

the general solution using the quadratic equation is:

So lets solve ( notice , , and )

Plug in a=1, b=4, and c=24

Square 4 to get 16

Multiply to get

Combine like terms in the radicand (everything under the square root)

Simplify the square root (note: If you need help with simplifying the square root, check out this solver)

Multiply 2 and 1 to get 2

After simplifying, the quadratic has roots of

or

RELATED QUESTIONS
solve the equation. Label solution as real, imaginary, and/or complex. x^2 - 2x +... (answered by Earlsdon)

How to solve 2x^2 + 1 = 0 using imaginary/complex... (answered by richwmiller)

Please help solve this equation with complex numbers, please show the steps (2-4j)x + 9... (answered by lynnlo)

please help me solve this equation using imaginary numbers {{{ sqrt(-12)... (answered by stanbon)

what are the complex zeros of y=X^3 I think the real zero is "0" and the other 2... (answered by solver91311)

Directions: Solve the equation by completing the square. Express any complex numbers... (answered by stanbon)

Directions: Solve the equation by completing the square. Express any complex numbers... (answered by fractalier)

Hi There! Can You Please Help Me Solve This?? I Just Don't Know How To Take The First... (answered by josgarithmetic)

Help please, thank you Solve the equation x^2 + 19 =0 The solution set is x =? (use... (answered by stanbon)