SOLUTION: I cannot understand how to solve the quadratic equation: -1+3x^2=2x I need to use the quadratic formula. My teacher wants us to leave it under the radical symbol if it is not a

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Question 139225This question is from textbook McDougal Littell Algebra 1
: I cannot understand how to solve the quadratic equation: -1+3x^2=2x
I need to use the quadratic formula. My teacher wants us to leave it under the radical symbol if it is not a perfect square. This question is from textbook McDougal Littell Algebra 1

Found 2 solutions by checkley77, solver91311:
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
-1+3x^2=2x
3x^2-2x-1=0

x=(2+-sqrt[-2^2-4*3*-1])/2*3
x=(2+-sqrt[4+12])/6
x=(2+-sqrt16)/6
x=(2+-4)/6
x=(2+4)/6
x=1 answer.
x=(2-4)/6
x=-2/6
x=-1/3 answer.
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!
First, put it into standard form:




Now you can see that , , and .

Substitute those values for a, b, and c into and do the arithmetic. You will find that this one is very tidy and well-behaved with a nice neat perfect square under the radical. That is to say, nothing like real life.
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