SOLUTION: The midpoint of AB is (3sqrt5,2sqrt3). If the coordinates of the endpoint B are (-sqrt5,1/2sqrt3), then what are the coordinates of endpoint A?

Question 138591: The midpoint of AB is (3sqrt5,2sqrt3). If the coordinates of the endpoint B are (-sqrt5,1/2sqrt3), then what are the coordinates of endpoint A?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The midpoint of AB is (3sqrt5,2sqrt3). If the coordinates of the endpoint B are (-sqrt5,1/2sqrt3), then what are the coordinates of endpoint A?
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Let the coordinates of A be (x,y)
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Note: The coordinates of the midpoint of a line segment are the average
of the coordinates of the endpoints.
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EQUATIONS:
(x + (-sqrt5))/2 = 3sqrt5
x - sqrt5 = 6sqrt5
x = 7sqrt5
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(y + 2sqrt3)/2 = (1/2)sqrt3
y + 2sqrt3 = sqrt3
y = -sqrt3
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The coordinates of A are (7sqrt5 , -sqrt3)
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Cheers,
Stan H.

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