SOLUTION: Solve for x: logbasex(3x+10)=logbase7 49

Algebra.Com
Question 138585: Solve for x: logbasex(3x+10)=logbase7 49
Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
log[x](3x+10)=log[7](49)
log[x](3x+10)=2
x^log[x](3x+10)=x^2
3x+10=x^2
x^2-3x-10=0
(x-5)(x+2)=0
x=5
.
Ed

RELATED QUESTIONS

how to solve logbase7 (x+5)-logbase7 *3=logbase7... (answered by rothauserc)
Solve for x: a) (log base2 x)^2-(logbase2 x^2)=0 b) log base2(logbasex 64)=1 c) log... (answered by stanbon)
PLEASE HELP ME:) ALGEBRAICALLY Solve: 1) logbase7 x - 1/2 logbase7 9 = logbase7 5... (answered by vleith)
PLEASE HELP ME SOLVE THIS PROBLEM. Logbase3(1+x)>(1-Logbasex(1-x))Logbase3x. Thank... (answered by kev82)
solve for 2x-y=10 and... (answered by oscargut)
Solve for x... (answered by josmiceli,Earlsdon)
How can I calculate... (answered by ewatrrr)
solve for the radical... (answered by nyc_function)
Solve: logbase3(logbasex(logbase4 16)) = 1 Solve: 6^2logbase6 X + logbase6 X =125... (answered by stanbon)