SOLUTION: How do I compute the x and y axis intercepts of a quadratic function? Please provide an example to illustrate the explanation. Thank you

Question 137128: How do I compute the x and y axis intercepts of a quadratic function? Please provide an example to illustrate the explanation. Thank you
Found 2 solutions by oscargut, Earlsdon:
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
if f(x)=ax^2+bx+c
then
y axis intercept is P=(0,f(0))=(0,c)
x axis intercept are the roots of f(x)

f(x)=x^2-5x+6
y axis intercept is P=(0,6)

x axis intercept are x=2 and x=3
point are (2,0) and (3,0)

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
You can find the x- and y-intercepts of a quadratic function as follows:
1) Set x = 0 and solve for y. This will give you the y-intercept.
2) Set y = 0 and solve for x. This will give you the x-intercept.
Here's an example:
Find the x- and y-intercepts.
1) Set x = 0 and solve for y.

The y-intercept is: (0, 12)
2) Set y = 0 and solve for x.
Factor the trinomial:
from which we get:
and These are the x-intercepts. These are also called the "zeros" or the "roots" of the equation and notice that they are "real" numbers, which really means that the equation has real x-intercepts.
Of course, not all quadratic equations will have x-intercepts but they will alway have a y-intercept.
Here's a graph of the given example:

Here's an example in which the quadratic equation has no x-intercepts.

1) Set x = 0 and solve for y.

This is the y-intercept.
2) Set y = 0 and solve for x.
Use the quadratic formula to solve: (You can do the details)
and No "real" roots so no x-intercepts.
Here's the graph:

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