SOLUTION: 4 over x = 3 over x squared + 5 LCD= x^2 a=5 b=-4 c=3 0=5x^2-4x+5 Total answer i got= 4 plus minus square root -44 over 10 is this right???? are they both no solution?

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Question 133900: 4 over x = 3 over x squared + 5
LCD= x^2
a=5 b=-4 c=3
0=5x^2-4x+5
Total answer i got= 4 plus minus square root -44 over 10
is this right???? are they both no solution?

Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
4/x=(3/x^2) +5 I assume that this is the problem.
4x=3+5x^2
5x^2-4x+3=0
x=2/5 + sqrt(11)/5 * i, x=2/5 - sqrt(11)/5 * i
.
Ed
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -44 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -44 is + or - .

The solution is , or
Here's your graph:




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