SOLUTION: Find the value of the discriminant and give the number of real solutions. 2x^2-5x=0

Question 133370: Find the value of the discriminant and give the number of real solutions.
2x^2-5x=0
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
From the quadratic formula

the discriminant consists of all of the terms in the square root. So the discriminant is

the discriminant tells us how many solutions (and what type of solutions) we can expect for any quadratic.

Now let's find the discriminant for :

Start with the given equation

Plug in a=2, b=-5, c=0

Square -5 to get 25

Multiply -4*2*0 to get -0

Combine 25 and -0 to get 25

Since the discriminant equals 25 (which is greater than zero) , this means there are two real solutions. Remember if the discriminant is greater than zero, then the quadratic will have two real solutions.

Notice if we graph , we get

and we can see that there are two real solutions. Remember if the discriminant is greater than zero, then the quadratic will have two real solutions.

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