SOLUTION: Hi.
Please help. I am lost-my mind is swimming with all the steps and I got lost twice-I need HELP!
The problem is: State the value of the discriminant and the number of real sol
Algebra.Com
Question 133011: Hi.
Please help. I am lost-my mind is swimming with all the steps and I got lost twice-I need HELP!
The problem is: State the value of the discriminant and the number of real solutions. t^2+14t+49=0
Thank You.
Found 2 solutions by jim_thompson5910, solver91311:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
From the quadratic formula
the discriminant consists of all of the terms in the square root. So the discriminant is
the discriminant tells us how many solutions (and what type of solutions) we can expect for any quadratic.
Now let's find the discriminant for :
Start with the given equation
Plug in a=1, b=14, c=49
Square 14 to get 196
Multiply -4*1*49 to get -196
Combine 196 and -196 to get 0
Since the discriminant equals 0 , this means there is one real solution. Remember if the discriminant is equal to zero, then the quadratic will have one real solution.
Notice if we graph , we can see that there is one real solution. So this verifies our answer.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
is the quadratic formula. The discriminant is the part under the radical, or
Your equation, is already in standard form, so just plug in the numbers:
is the value of the discriminant.
A discriminant of 0 means that there are two real and identical roots (or 1 real root with a multiplicity of 2, depending on the terminology you have been taught)
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