SOLUTION: Solve : 3(2^(2x)) - 2^(x+2) +1=0 I am having real trouble with this one , I hope someone can help me:)

Algebra.Com
Question 132874: Solve : 3(2^(2x)) - 2^(x+2) +1=0
I am having real trouble with this one , I hope someone can help me:)

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Solve : 3(2^(2x)) - 2^(x+2) +1=0
3(2^(2x) -[2^x*2^2] + 1 = 0
3(2^2x) -4(2^x] + 1 = 0
-------------
Let 2^x = w
-------------
Rewrite the equation in "w":
3w^2 -4w + 1 = 0
Factor:
(3w-1)(w-1) = 0
w = 1/3 or w = 1
------------------
Rewrite in terms of "x":
2^x = (1/3) or 2^x = 1
x = [log(1/3)]/[log2] or x = [log1]/[log2]
x = -1.58496... or x = 0
=============================
Cheers,
Stan H.

RELATED QUESTIONS

I am having trouble. Can someone please help me. Solve:... (answered by Earlsdon)
I am having trouble with this problem can someone please help? Multiply... (answered by nyc_function)
Can someone please help me solve this problem. I am having trouble understanding how to... (answered by checkley71)
I am having trouble with this quadratic equation. {{{2x(x+3)=0}}}Can someone please... (answered by Earlsdon)
Can someone please help me solve this problem. I am having a lot of trouble working it... (answered by funmath)
I'm having trouble solving this problem for some reason. I am not understanding how to... (answered by mananth)
I am having trouble with this equation: m^2 - 1 / (m + 1)^2. Can someone please help me... (answered by stanbon)
Hi, I am having trouble with my homework. I hope someone helps me with this. Prove... (answered by lwsshak3)
I am having trouble dividing fractions. Can someone please help me. 3 1/5+ 2... (answered by stanbon)