SOLUTION: PLease help me solve this equation.I am suck. A line is located at (1,3) and (4,-2).Where is the slope. I got -5/3 Thank YOu!

Question 132175: PLease help me solve this equation.I am suck.
A line is located at (1,3) and (4,-2).Where is the slope.
I got -5/3
Thank YOu!
Answer by nycsharkman(136) (Show Source): You can put this solution on YOUR website!
The slope is the rise over the run or rise/run.
Your question:
A line is located at (1,3) and (4,-2).Where is the slope.
I got -5/3
Thank You!
Let (1,3) = (a, b)
Let (4,-2) = (c, d)
Slope = d minus b divided by c minus a
We now plug and chug!
Slope = -2 - 3/4 - 1
Slope = -5/3
You did great!
This slope is negative, which means the line of this graph is slanted from the left side falling down to the right side of the coordinate plane.

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