SOLUTION: Solve: a) log(x-2)+log(x+1)=1 b) 4(^1-x)=3*5^x c) logbase2(1-x)+logbase2(4x+1)=0

Question 129852: Solve:
a) log(x-2)+log(x+1)=1
b) 4(^1-x)=3*5^x
c) logbase2(1-x)+logbase2(4x+1)=0
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
a)
log(x-2)+log(x+1)=1
log((x-2)(x+1))=1
log(x^2-x-2)=1
10^log(x^2-x-2)=10^1
x^2-x-2=10
x^2-x-12=0
(x-4)(x+3)=0
x=4, x=-3 (extraneous)
x=4
.
c)
logbase2(1-x)+logbase2(4x+1)=0
log[2]((-x+1)(4x+1))=0
log[2](-4x^2+3x+1)=0
2^log[2](-4x^2+3x+1)=2^0
-4x^2+3x+1=1
-4x^2+3x=0
x(-4x+3)=0
x=0, x=3/4
.
Ed

RELATED QUESTIONS
Solve:... (answered by stanbon)

SOLVE for x: a) logbase3 x + logbase3 (x-8)=2 b) logbase4 (x+2)+logbase4(x-4)=2 c)... (answered by edjones)

Please help me solve for x: a) logbase12(x^2-x)=1 b) (logbase2 x)^2-6*(logbase2 x)... (answered by edjones)

Solve for x: a) (log base2 x)^2-(logbase2 x^2)=0 b) log base2(logbasex 64)=1 c) log... (answered by stanbon)

solve the simultaneous equation 2(logbase2 tox-1)=logbase2 to y ......eq1 y=x-1 (answered by Alan3354)

solve: -2logbase4x=logbase49 {{{-2*log( 4, x ) = log( 4, 9 )}}} 3 logbase2... (answered by ichudov)

Please solve log base... (answered by Alan3354,stanbon)

Solve for "x" logbase2 4 + logbase2 27= logbase2... (answered by Alan3354,nerdybill)

Solve: a) logbase5 6-logbase5 x=logbase5 2 b) logbase2 8-logbase2 4=x c) logbase3 27+... (answered by stanbon)