SOLUTION: Hello I am have difficulty trying to work this one out, your assistance would be greatly appreciated. Ta. I am asked to solve 6(3X-4)^2-7(3X-2)-5=0 using the quadratic equation.

Question 128516: Hello
I am have difficulty trying to work this one out, your assistance would be greatly appreciated. Ta.
I am asked to solve 6(3X-4)^2-7(3X-2)-5=0 using the quadratic equation.
The following is what I have tried
6(3X-4)^2-7(3X-2)-5=0
then becomes
6(3X-4)(3X-4)-21X+14-5=0
then becomes
(18X-24)(3X-4)-21X+9=0
then becomes
54X^2-72X-72X+96-21X+9=0
then becomes

54X^2-165X+105=0
This is as far as I could go, and have come to the conclusion that it cannot be done. Can you please confirm this for me, and show me the whys and hows, with an explanation please. Thank you. Cheers D.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
54x^2-165x+105=0

x=(165+-sqrt[-165^2-4*54*+105])/2*54
x=(165+-sqrt[27225-22680])/108
x=(165+-sqrt4545])/108
x=(165+-67.42)/108
x=(165+67.42)/108
x=(232.42)/108
x=2.152answer.
x=(165-67.42)/108
x=-97.58/108
x=-.9035 answer.
RELATED QUESTIONS
Hi I am stuck on this one which has me completely bamboozled. Your assistance would be... (answered by solver91311,stanbon)

Hello. I am having a little difficulty with this problem. It says to use the pi key... (answered by htmentor)

Hello, I am needing some help in trying to figure out how to solve this equation:... (answered by tutorcecilia)

Hello I am currently trying to figure out this problem. Find all real and imaginary... (answered by jim_thompson5910)

I am asked to find all solutions, real or complex: (3x+1)^2=-12 I have no idea how... (answered by ankor@dixie-net.com)

Hello, I am having some difficulty constructing this truth table. I have been working (answered by jim_thompson5910)

Hello, I am trying to solve for the rate 980(1+r)^20 = 3725.37 I know the answer is (answered by stanbon)

Hello, I am trying to figure out how to write this function in vertex form. The question (answered by Alan3354)

I am having difficulty on the steps to solve this equation: e^-x = (e^4)^x+3 Any... (answered by ankor@dixie-net.com)