SOLUTION: The length of a rectangle is 50ft. The perimeter of the rectangle is 275ft more than the width of the rectangle. Find the width.
Here's what I have
2(50)+2w = 275-w
100+2w = 2
Algebra.Com
Question 127313: The length of a rectangle is 50ft. The perimeter of the rectangle is 275ft more than the width of the rectangle. Find the width.
Here's what I have
2(50)+2w = 275-w
100+2w = 275-w
+w +w
100+3w = 275
-100 -100
3w - 175
3w/3 175/3
w=58.3333...
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
Looks like the correct answer to me. :)
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