SOLUTION: The sum of a number, five-fourths of the number, and a third of the number is one hundred fifty-five. Find the number. Here's what I have x + x + 5/4 + x + 1/3 + x =155 4x + 5

Question 127308: The sum of a number, five-fourths of the number, and a third of the number is one hundred fifty-five. Find the number.
Here's what I have
x + x + 5/4 + x + 1/3 + x =155
4x + 5/4 + 1/3 =155
5/4 + 1/3= 1 7/12
4x = 1 7/12
?????
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You're on the right track, but "five-fourths of the number" does not translate to . It translates to where the is multiplied by x. The same applies to the statement "third of the number "

So our equation should look like this:

Multiply both sides by the LCD of 12 (the LCD is the LCM of the denominators). This will eliminate the fractions (note: if you need help with finding the LCM, check out this solver)

Distribute and multiply the LCM to each side

Combine like terms on the left side

Divide both sides by 31 to isolate x

Divide

--------------------------------------------------------------
Answer:
So our answer is

So the number is 60
RELATED QUESTIONS
The sum of a number and seven is fifty-five. Find the number. (answered by rapaljer)

Three times the sum of two times a number and five is... (answered by ewatrrr)

The sum of a number, one third of the number, and thirty is fifty (answered by JulietG)

"the sum of five and eight times a number is the same as fifty plus one-half the number.... (answered by stanbon)

Three-fourths of a number minus five-eighths equals one-half. Find the number. (answered by Alan3354)

FIVE MORE THAN THREE-FOURTHS OF A NUMBER c IS 26. FIND THE NUMBER (answered by nerdybill)

the sum of three integers is one hundred twenty-three. The second number is two more... (answered by ankor@dixie-net.com)

One hundred and eighty is the product of a number and another number that is five times... (answered by MathLover1)

five more than one third of a number is -2 find the... (answered by rfer)