SOLUTION: Algebraically solve: 70=6+8(^3x-1)

Question 122243: Algebraically solve: 70=6+8(^3x-1)
Answer by jainenderkapoor(61) (Show Source): You can put this solution on YOUR website!
Algebraically solve: 70=6+8(^3x-1)
70 - 6 = 8^(3x -1)
64 = 8^(3x -1)
8^2 = 8^(3x -1)
Comparing both sides we get -- exponents to be same
2 = 3x - 1
2 + 1 = 3x
3 = 3x
x = 3/3 = 1
Hope the solution is clear to you. If you need any help, I am available for Online Tutoring at very reasonable rates. My email is is jainenderkapoor@gmail.com
RELATED QUESTIONS
How do I solve 3x-5y=-11 and x+2y=6 algebraically? 2x+y=-3... (answered by glitzgirl_14)

Solve Linear Systems Algebraically. x+ 4y = 1 3x + 2y = -12 and 3x + 2y = 6... (answered by mananth)

Solve the inequality algebraically... (answered by ewatrrr)

How do i Solve algebraically... (answered by Fombitz)

Solve the system algebraically 5x + 2y = 10 3x + 2y =... (answered by Alan3354)

solve by substitution: 1/3x + 1/5y= 8/15 and 1/3x + 4y... (answered by Edwin McCravy)

solve each system of equations algebraically 3x-2y=8... (answered by user_dude2008)

solve the following equations; 3x+2y+7=0 6x+4y-8=0, a. algebraically b.... (answered by mananth)

Solve algebraically X+2>3x-8 Please provide steps to your... (answered by Fombitz)