SOLUTION: The area of a playground is 153 m square if the length of the playground is decreased by 4 m and the breadth is increased by 4 m if playground become a square decide of the square

Question 1207564: The area of a playground is 153 m square if the length of the playground is decreased by 4 m and the breadth is increased by 4 m if playground become a square decide of the square in metre is
Found 2 solutions by mananth, greenestamps:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
The area of a playground is 153 m square if the length of the playground is decreased by 4 m and the breadth is increased by 4 m if playground become a square decide of the square in metre is
The problem is not written correctly. I presume we have to find the length of side of the square

Assume x is length and y is width
xy = 153 given
x =153/y
given condition length is reduced by 4 and width increased by 4
(x-4)((y+4) is the area now and it is a square
sides are equal
substitute x
((153/y) -4)=(y+4)
(153-4y)/y = y+4
153 -4y = y^2+4y
y^2+8y-153=0
y^2+17y-9y-153=0
y(y+17)-9(y+17)=0
(y-9)(y+17)=0
y = 9 or -17
ignore negative
y= 9 , x =17 the original dimensions

17-4=13
9+4=13
the sides are 13 m

Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!

We can work the problem "backwards": start with the square of side length x, then increase one dimension by 4m and decrease the other by 4m to get a rectangular playground with area 153 m^2.

ANSWER: the side length of the square is 13m

CHECK: (x-4)(x+4) = (13-4)(13+4) = 9*17 = 153

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