SOLUTION: The admission fees at an amusement park are $2.50 for children and $5.20 for adults. On a certain day, 273 people entered the park, and the admission fees collected totaled $1,128.

Question 1202653: The admission fees at an amusement park are $2.50 for children and $5.20 for adults. On a certain day, 273 people entered the park, and the admission fees collected totaled $1,128.00. How many children and how many adults attended the amusement park that day?
There were children and adults that attended the amusement park that day.
Answer by Edwin McCravy(20054) (Show Source): You can put this solution on YOUR website!

Here's one exactly like it.  It can be done with 1 unknown or 2 unknowns. It
is easier to set up in two unknowns.  Maybe another tutor will solve it using
only one unknown.  Here is the problem I solved with different numbers, using
two unknowns:

The admission fees at an amusement park are $3.10 for children and $5.80 for
adults. On a certain day, 443 people entered the park, and the admission fee
collected totaled $2,051.00. How many children and how many adults attended the
amusement park that day?

Let c = number of children
let a = number of adults

                          | money |
                          | taken |
         | number | price |  in   | 
children |    c   |  3.10 | 3.10c |
adults   |    a   |  5.80 | 5.80a |
-----------------------------------
totals   |  443   |-------| 2051  |

First equation from first column    c + a = 443
Second equation from last column  3.10c + 5.80a = 2051

    

solve the first equation for c:

c = 443 - a

Substitute in the second equation:

  3.10(443 - a) + 5.80a = 2051

1373.30 - 3.10a + 5.80a = 2051

        1373.30 + 2.70a = 2051

                  2.70a = 677.70

                      a = 251

Substitute in

                      c = 443 - a

                      c = 443 - 251

                      c = 192

So there were 251 adults and 192 children.

Now do yours the exact same way.

Edwin

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