.
Maricopa's Success scholarship fund receives a gift of $105000.
The money is invested in stocks, bonds, and CDs.
CDs pay 3.25% interest, bonds pay 5.7% interest, and stocks pay 11.5% interest.
Maricopa Success invests $35000 more in bonds than in CDs.
If the annual income from the investments is $7937.50, how much was invested in each account?
~~~~~~~~~~~~~~
Let x be the amount invested in CDs at 3.25%.
Then the amount invested in bonds at 5.7% is (x+35000) dollars, according to the problem.
The amount invested at 11.5% is the rest (105000 - x - (x+35000)) = 70000-2x dollars.
Next write the total interest equation
0.0325x + 0.057(x+35000) + 0.115*(70000-2x) = 7937.50 dollars.
Simplify and find x
0.0325x + 0.057x - 0.115*(2x) = 7937.50 - 0.057*35000 - 0.115*70000
-0.1405x = -2107.50
x = = 15000.
ANSWER. $15000 was invested at CD (at 3.25%); $15000+$35000 = $50000 was invested in bonds at 5.7%
and the rest 105000-15000-50000 = 40000 dollars were invested in stocks (at 11.5%).
CHECK. 0.0325*15000 + 0.057*50000 + 0.115*40000 = 7937.50 dollars, total annual interest. ! correct !
Solved, using one single equation in one single unknown.