SOLUTION: A ball is thrown upward. The path of the ball is modelled by the equation: h=-4.9t^2 + 9.9t + 1, where h is the height of the ball above the ground (in meters) and t is time (in se

Question 1198104: A ball is thrown upward. The path of the ball is modelled by the equation: h=-4.9t^2 + 9.9t + 1, where h is the height of the ball above the ground (in meters) and t is time (in seconds).
Time (s) Height (m)
0.0
0.5
1.0
1.5
2.0
2.5
3.0
a) How long will it take the ball to reach the maximum height?

b) After how many seconds will the ball land?

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A ball is thrown upward. The path of the ball is modelled by the equation: h=-4.9t^2 + 9.9t + 1, where h is the height of the ball above the ground (in meters) and t is time (in seconds).
Time (s) Height (m)
0.0
0.5
1.0
1.5
2.0
2.5
3.0
a) How long will it take the ball to reach the maximum height?
It's a parabola.
The vertex, max height, is at t = -b/2a
=======================
b) After how many seconds will the ball land?
When h=-4.9t^2 + 9.9t + 1 = 0

RELATED QUESTIONS
the height of a ball thrown upward after a given amount of time is h = - 4.9t ^ 2 + 29.4t (answered by Solver92311,ikleyn)

Grade 10 solve using the quadratic formula- The height of a ball thrown upward after a... (answered by Solver92311,ikleyn)

Grade 10- The height of a ball thrown upward after a given amount of time is h = - 4.9t ^ (answered by Boreal,ikleyn)

Hello, can you please help me with this question? A ball is thrown upward with an initial (answered by ikleyn)

Please help me answer this word problem!! Use function notation to rewrite all of the... (answered by ikleyn)

the height of an object is given by s=-9t^2+vt+s0 where v is the initial velocity and s0... (answered by ikleyn)

If someone could help me find the answer. I have been doing this problem over and over. (answered by greenestamps)

A firework is launched upward at an initial velocity of 49 m/s, from a height of 1.5 m... (answered by Boreal,ikleyn)

The height of a ball thrown straight upward is measured by the function h(t)=-16t^2+40t. (answered by richwmiller)