Find two consecutive negative odd integers such that 5 times the first plus the square of the second equals -14.
- 3 and - 1
Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!
(1) Never solve a quadratic equation the way tutor @josgarthmetic did:
looks like...
(2) The solution from tutor @ewatrrr is algebraically sound; but the problem specified that the two integers are odd.
To avoid overlooking the fact that the problem asks for consecutive odd integers, you can use "2n-1" and "2n+1" for the two integers; then an integer solution for n will guarantee that the two integers are odd.
or
n must be an integer, so we reject the solution n = -5/2; the single solution to our equation is n = -1.
That gives us, for the two consecutive negative odd integers that we are looking for,
2n-1 = 2(-1)-1 = -2-1 = -3
2n+1 = 2(-1)+1 = -2+1 = -1
ANSWERS: -3 and -1
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