Hi Determine the coordinates of the point(s) of intersectio y = x^2-7x+15 and y = 2x-5. x^2-7x+15 = 2x-5 x^2 - 9x + 20 = 0 | Factor (x - 4)(x - 5) = 0 x = 4 0r x = 5 And y = 3 0r y = 5 | Substitute value of x into y = 2x-5 point(s) of intersection: P(4,3)and P(5,5) Graphing x^2-7x+15 Green y = 2x-5 BlueWish You the Best in your Studies.
Reduce two starting equations to one single equation for x, eliminating y x^2 - 7x + 15 = 2x - 5 Write it in the standard form x^2 - 9x + 20 = 0 Factor left side (x-4)*(x-5) = 0 The roots are 4 and 5. For each root calculate y= = 2*4 - 5 = 3; = = 2*5 - 5 = 5. ANSWER. There are 2 solutions: (1) (x,y) = (4,3) and (2) (x,y) = (5,5).