SOLUTION: find two consecutive positive integers such that the square of the second integer added to four times the first is equal to 41

SOLUTION: find two consecutive positive integers such that the square of the second integer added to four times the first is equal to 41

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Question 1195914: find two consecutive positive integers such that the square of the second integer added to four times the first is equal to 41
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
find two consecutive positive integers such that the square of the second integer added to four times the first is equal to 41
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n^2 + 4(n-1) = 41
n^2 + 4n - 45 = 0
(n-5)*(n+9) = 0
n = 5

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