SOLUTION: solve quadratic equation by factoring x^2+15x=-50

Question 1193600: solve quadratic equation by factoring
x^2+15x=-50
Found 2 solutions by greenestamps, josgarithmetic:
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

(1) Get all terms on one side of the equation (add 50 to both sides):

(2) You want to factor this as the product of two linear expressions. The constant term is positive, so the signs of the two expressions are the same; and the linear term is positive, so the signs of the two expressions are both positive. So the factoring will be of the form

So you want a and b to be two positive integers whose sum is 15 and whose product is 50 -- 5 and 10. So

The product is 0 if and only if one of the factors is 0:

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ANSWERS: x=-5 and x=-10

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
By FACTORING,
x^2+15x=-50
x(x+15)=-50
Factorizations for 50:

But for two numbers to give -50, and they differ each other by 15, look at either
-5 and 10
or
5 and -10.

If x=-5, then x+15=-5+15=10.
You could check to see if the other combination does or does not also work.
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