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The graph of a certain quadratic y = ax^2 + bx + c is a parabola with vertex (-4,0)
which passes through the point (1,-75). What is the value of a?
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Hello, you do not need make all these calculations and transformations,
which @MathLover1 makes in her post.
The solution is in couple of lines below.
You are given that a quadratic function is a parabola with vertex (-4,0).
It means that the function in vertex form is
y = a*(x-(-4))^2 + 0 = a*(x+4)^2. (1)
The only unknown is the parameter "a". To find it, use the given part, which says
that the parabola passes through the point (1,-75).
So, at x= 1 the value of the function (1) should be -75. You write this equation, based on (1)
-75 = a*(1+4))^2, or -75 = a*5^2, which is 25a = -75.
From this equation, a = = -3.
ANSWER. The value of "a" is -3.
Solved.