SOLUTION: the roots of 2x^2 +3x-1=0 are alpha and beta. Find the values of [alpha square +1÷beta square] [beta square+1÷alpha square]

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Question 1187915: the roots of 2x^2 +3x-1=0 are alpha and beta. Find the values of [alpha square +1÷beta square] [beta square+1÷alpha square]

Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.
the roots of 2x^2 +3x-1=0 are alpha and beta.
Find the values of [alpha square +1÷beta square] [beta square+1÷alpha square]
~~~~~~~~~~~~~~~~~ 

To make my writing easier, I will use  "a" instead of alpha  and "b" instead of bete.


So, I need find  .



We have

     =  + 1 + 1 + .



According to Vieta's theorem,   = .  THEREFORE,   =  = .


HENCE,  
    
     =  + 1 + 1 +  = + 2 + 4 = 6  = 6.25.    ANSWER

Solved.




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