SOLUTION: NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)= −4.9t2^ + 211t + 276. Assuming that the rocket will spl

Question 1187326: NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)= −4.9t2^ + 211t + 276.

Assuming that the rocket will splash down into the ocean, at what time does splashdown occur? For intermediate work, keep at least five decimal places. For the final answer, round to the nearest hundredth.

How high above sea-level does the rocket get at its peak?

Answer by ikleyn(52768) (Show Source): You can put this solution on YOUR website!
.


To answer first question, solve this quadratic equation

    -4.9t^2 + 211t + 276 = 0

and use its greatest (positive) root.




To answer second question, you should know from the given height equation

that the gravity acceleration is  g = 4.9*2 = 9.8 m/s^2,  the initial velocity is v = 211 m/s, and starting height is h = 276 m.


Then the maximum height is   =  +  =  +  = 2547.48 meters.    ANSWER

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