SOLUTION: Suppose that the population of a town is given by P = 0.16t^2 + 7.2t +100 where P is the population in thousands and t is the time in years, with t = 0 representing the year 2000.

Question 1181718: Suppose that the population of a town is given by P = 0.16t^2 + 7.2t +100 where P is the population in thousands and t is the time in years, with t = 0 representing the year 2000.

a) What was the population in 2010?
Found 2 solutions by htmentor, Solver92311:
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
The equation for the population as written will never allow the population to
reach 52,000 for any positive value of t.
If P = 0.16t^2 + 7.2t + 100 represents the population in thousands, then
the population at t = 0 is 100,000. Any positive values of t will only make
the population get larger, so this will not work.
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!

Write the Population function in pencil. Erase and replace each instance of "t" with 10. Do the arithmetic.

John

My calculator said it, I believe it, that settles it

From
I > Ø

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