SOLUTION: Use the quadratic formula to determine, accurate to one decimal place, the roots, if they exist, for each quadratic relation.
a) y = 2x2 + 3x + 1
b) y = x2 - 3x + 5
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Question 1180546: Use the quadratic formula to determine, accurate to one decimal place, the roots, if they exist, for each quadratic relation.
a) y = 2x2 + 3x + 1
b) y = x2 - 3x + 5
c) y = x2 + x - 5
d) y = - 9x2 - 6x + 1
Found 2 solutions by mananth, MathLover1:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
2x2 + 3x + 1=0
comparing with ax^2 +bx +c =0
using the Quadratic Formula where
a = 2, b = 3, and c = 1
b^2-4ac= 9 + -8
b^2-4ac= 1
substitute the values in the formula
x1=( -3 + 1 )/ 4
x1= -0.5
x2=( -3 -1 ) / 4
x2= -1
Now you know thesteps
solve the rest of them
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
a)
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solutions:
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b)
...in your case ,, and
solutions:
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c)
...in your case ,, and
solutions:
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d)
...in your case ,, and
...simplify
solutions:
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