SOLUTION: A rectangular chicken yard was built against an existing shed wall. 30 m of fencing was used to enclose 108 m2. Find the dimensions of the yard.

Question 1180466: A rectangular chicken yard was built against an existing
shed wall. 30 m of fencing was used to enclose 108 m2.
Find the dimensions of the yard.

Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
A rectangular chicken yard was built against an existing
shed wall. 30 m of fencing was used to enclose 108 m2.
Find the dimensions of the yard.
~~~~~~~~~~~~~~~

Let x be the width perpendicular to the wall, in meters. Then the length parallel to the wall is (30 - 2x) meters. The area is x*(30-2x), and it is 108 m^2, according to the condition. So, x*(30-2x) = 108 is your area equation to find x. Simplify 30x - 2x^2 = 108 2x^2 - 30x + 108 = 0 x^2 - 15x + 54 = 0 (x-6)*(x-9) = 0 There are two roots, 6 and 9, and they BOTH are meaningful. ANSWER. There are two solutions. One solution is (the width = 6 m perpendicular to the wall, the length is 30-2*6 = 18 m parallel to the wall). The other solution is (the width = 9 m perpendicular to the wall, the length is 30-2*9 = 12 m parallel to the wall).

Solved.

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Regarding the post by @MathLover1, she made an arithmetic error on the way, so her solution is FATALLY WRONG.

For your safety, ignore her post.

Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

A rectangular chicken yard was built against an existing
shed wall.
given area:
...solve for
.........eq.1
if of fencing was used to enclose , and chicken yard was built against an existing
shed wall, we say that
.........substitute

.......both sides multiply by

...simplify
...factor

positive solution:
=>
go to
.........eq.1,...substitute

the dimensions of the yard are: by

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