SOLUTION: How do I solve x^2+6x+4=0 in quadratc formula? I think this is how to slove x= -6+or-√6^2-4(x)(4)/2(x) -6+or-√36-4(x)(4)/2(x)

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Question 117555: How do I solve x^2+6x+4=0 in quadratc formula?
I think this is how to slove x= -6+or-√6^2-4(x)(4)/2(x)
-6+or-√36-4(x)(4)/2(x)
-6+or-√36-16/2(x)
-6+or-√20/2
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Let's use the quadratic formula to solve for x:


Starting with the general quadratic



the general solution using the quadratic equation is:





So lets solve ( notice , , and )




Plug in a=1, b=6, and c=4



Square 6 to get 36



Multiply to get



Combine like terms in the radicand (everything under the square root)



Simplify the square root (note: If you need help with simplifying the square root, check out this solver)



Multiply 2 and 1 to get 2

So now the expression breaks down into two parts

or


Now break up the fraction


or


Simplify


or


So these expressions approximate to

or


So our solutions are:
or

Notice when we graph , we get:



when we use the root finder feature on a calculator, we find that and .So this verifies our answer
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