SOLUTION: I am having some troubles with solving for the variable in equation {{{2(y-1)^2=4(y+1)^2}}} What I have so far is...... 2(y-1)(y-)=4(y+1)(y+1) 2(y^2-y-y-1)=4(y^2+y+y+1) 2y^2-

Question 117427: I am having some troubles with solving for the variable in equation
What I have so far is......
2(y-1)(y-)=4(y+1)(y+1)
2(y^2-y-y-1)=4(y^2+y+y+1)
2y^2-2y-y2-2=4y^2+4y+4y+4
2y^2-4y-2=4y^2+8y+4
But i can not get any further....can you please help
Thank you so much!!!!
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

Subtract from both sides

Add to both sides

Subtract from both sides

divide both sides by

Now subtract from both sides

Now complete the square by taking 1/2 of the
coefficient of y, square it, and add it to both sides

Take the square root of both sides

answer
answer
check answer

OK
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