SOLUTION: When a pendulum that is 0.5m long swings back and forth, its angular displacement, theta , in radians, from rest is given by theta= (1/4 sin( pi/2t), where t is the time , in seco

Question 1173664: When a pendulum that is 0.5m long swings back and forth, its angular displacement, theta , in radians, from rest is given by theta= (1/4 sin( pi/2t), where t is the time , in seconds.
a) what is the period...I think it is 4??
b) At waht time is the pendulum first displaced by an angle of 0.1 radians? no idea

Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
The general form for the pendulum motion is theta(t) = A*sin(wt), where A is
the amplitude and w is the angular velocity.
So the amplitude is 0.25 and the angular velocity of the pendulum
is w = pi/2 rad/s.
a) The period, T is given by 2*pi/w = 4 s
b) 0.1 = 0.25*sin(pi/2*t) -> t = arcsin(0.1/0.25*2/pi) -> t = 0.262 s
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