SOLUTION: The height {{{highlight(in_feet)}}} of a ball above the ground t seconds after it is thrown is h(t) = 20+32t−16t2. How long will it take for the ball to hit the ground?

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Question 1173412: The height of a ball above the ground t seconds after it is thrown is h(t) = 20+32t−16t2. How long will it take for the ball to hit the ground?
Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.

To answer the problem's question, you need to solve this equation

    -16t^2 + 32t + 20 = 0


and take its larger root.


The equation is equivalent to

    4t^2 - 8t - 5 = 0


Use the quadratic formula

    t =  =  = .


The larger root is   =  = 2.5 seconds.


ANSWER.  The ball will hit the ground in 2.5 seconds.

Solved.



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