SOLUTION: A diver jumps from a platform 15 meters above the surface of the water. The diver's height, in meters, above the water is given by the equation h(t)=-4.9t^2 + 5.5t + 15 where t is

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Question 1173309: A diver jumps from a platform 15 meters above the surface of the water. The diver's height, in meters, above the water is given by the equation h(t)=-4.9t^2 + 5.5t + 15 where t is the time in seconds after the diver jumps. What is the max height of the diver and how long does it take the diver to reach that height?
Answer by Solver92311(821)   (Show Source): You can put this solution on YOUR website!


Since the lead coefficient is negative, the graph of the quadratic function is a concave down parabola. Since the value of the function is the height at time , the value of the function at the vertex is the maximum height attained by the diver. The value of the independent variable in at the vertex is . The value of the function at that point is . You can do your own arithmetic.


John

My calculator said it, I believe it, that settles it

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