.
In this problem, we take the gravity acceleration equal to 10 m/s^ (by rounding the true value of 9.81 m/s^2).
Then the equation for the height is
h(t) = -5t^2 + 35t.
To answer first question, solve the equation
-5t^2 + 35t = 25.
It is equivalent to
5t^2 - 35t + 25 = 0, or
t^2 - 7t + 5 = 0
= = =
There are two time moments
= = 0.8 seconds (rounded) moving up and
= = 6.2 seconds (rounded) moving down.
To answer the second question, you need solve this equation
-5t^2 + 35t = 0.
Factor left side
-5t*(t-7) = 0
and get the root t = 7. So, an object will hit ground in 7 seconds.
To answer the third question, notice that the parabola has the maximum at the midpoint between its y-intersections,
that are 0 and 7.
So, the maximum height is achieved at t= = 3.5 seconds,
and the maximum height is
h(7.5) = -5*3.5^2 + 35*3.5 = 61.25 meters.
Solved. // All questions are answered.
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In this site, there is a bunch of lessons on a projectile thrown/shot/launched vertically up
- Introductory lesson on a projectile thrown-shot-launched vertically up
- Problem on a projectile moving vertically up and down
- Problem on an arrow shot vertically upward
- Problem on a ball thrown vertically up from the top of a tower
- Problem on a toy rocket launched vertically up from a tall platform
Consider these lessons as your textbook, handbook, tutorials and (free of charge) home teacher.
Read them attentively and learn how to solve this type of problems once and for all.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
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Do not forget to post your "THANKS" for my teaching.