SOLUTION: Determine the equation of the quadratic given roots-1/3, -2/5 The answer must be in the form ax^2+bx+c=0 I got 15x^2+11x+6=0 I need help...I dont think this is right but when

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Question 1171274: Determine the equation of the quadratic given roots-1/3, -2/5
The answer must be in the form ax^2+bx+c=0
I got 15x^2+11x+6=0
I need help...I dont think this is right but when the equation wasn't expanded and it had the brackets it made sense
Found 2 solutions by ikleyn, ankor@dixie-net.com:
Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.

An equation is  


     = 0 


where each linear binomial factor is ASSOCIATED by the OBVIOUS way with the  roots.


It is the same as


     = 0 


which is EQUIVALENT to


    (3x+1)*(5x+2) = 0.


To get the standard form of a quadratic equation, make FOIL to get


    15x^2 + 6x + 5x + 6 = 0,


Combining like terms, you get the FINAL ANSWER


    15x^2 + 11x + 6 = 0.

Solved, explained and completed.



Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
Determine the equation of the quadratic given roots-1/3, -2/5
The answer must be in the form ax^2+bx+c=0
:
We got
x = - 1/3
3x = -1
3x + 1 = 0
and
x = -2/5
5x = -2
5x + 2 = 0
FOIL (3x+1)(5x+2)
15x^2 + 6x + 5x + 2 = 0
15x^2 + 11x + 2 = 0 is what I get


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