SOLUTION: Just simply rewrite the given equation to its standard form of quadratic equation then find the value of a, b and c x/(x-5)

SOLUTION: Just simply rewrite the given equation to its standard form of quadratic equation then find the value of a, b and c x/(x-5) - 3/(x+1) = 30/(x2-4x-5)

Question 1171029: Just simply rewrite the given equation to its standard form of quadratic equation then find the value of a, b and c
x/(x-5) - 3/(x+1) = 30/(x2-4x-5)
Found 2 solutions by Theo, MathTherapy:
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
standard form of the equation is ax^2 + bx + c = 0

a is the coefficient of the x^2 term.
b is the coefficient of the x term.
c is the constant term.

to get the equation into this form, subtract 30/(x^2-4x-5) from both sides to get:

x/(x-5)-3/(x+1)-30/(x^2-4x-5) = 0

multiply both sides of the equaton by x^2-4x-5 to get:

x*(x^2-4x-5)/(x-5) - 3*(x^2-4x-5)/(x+1) - 30 = 0

if you factor x^2-4x-5, you get (x-5)*(x+1).

replace x^2-4x-5 with (x-5)*(x+1) to get:

x*(x-5)*(x+1)/(x-5) - 3*(x-5)*(x+1)/(x+1) - 30 = 0

simplify to get:

x*(x+1) - 3*(x-5) - 30 = 0

simplify further to get:

x^2 + x - 3x + 15 - 30 = 0

combine like terms to get:

x^2 - 2x - 15 = 0.

the equation is now in standard form, where:

a = 1
b = -2
c = -15

what i found when i solved for x in both equaion was:

for x^2 - 2x - 15, y = 0 when x = 5 or x = -3

for x/(x-5)-3/(x+1)-30/(x^2-4x-5), y = 0 when x = -3.
when x = 5, the denominator in the equation became 0, making x = 5 not a solution to this equation.

since you have to go back to the original equation to test out your solution, it appears that the only solution for the original equation is x = -3, even though x = 5 was a solution for the modified equation.

you were not, however, asked to find a solution.
you were only asked to rewrite the equation to make it in the standard form of a quadratic equation.

i believe i did that correctly, getting you:

x^2 - 2x - 15 = 0, where:

a = 1
b = -2
c = -15

i believe that's your solution.
i couldn't see any other way to get it into standard form.

`

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Just simply rewrite the given equation to its standard form of quadratic equation then find the value of a, b and c
x/(x-5) - 3/(x+1) = 30/(x2-4x-5)

Correct answer: Compare the above to , and you'll see that:
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