SOLUTION: A model rocket is launched from the top of a building. The height (in meters) of the rocket above the ground is given by ℎ(𝑡) = −16𝑡^2 + 24𝑡 + 14, where t is the time

Question 1169690: A model rocket is launched from the top of a building. The height (in meters) of the rocket above the ground is given by ℎ(𝑡) = −16𝑡^2 + 24𝑡 + 14, where t is the time (in seconds) since the rocket was launched. What is the rocket’s maximum height?
Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
the maximum height is when t=-b/2a
that is t=-24/-32 or at t=2/3 sec
h(3/4)=-9+18+14
=23 m

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
A model rocket is launched from the top of a building. The height (in meters) of the rocket above the ground
is given by ℎ(𝑡) = −16𝑡^2 + 24𝑡 + 14, where t is the time (in seconds) since the rocket was launched.
What is the rocket’s maximum height?
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As the problem is worded, printed, posted and presented, it is

         a)   INCORRECT.
    and
         b)   clearly shows that the person who created it, does not know the subject.

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See the lessons
    - Introductory lesson on a projectile thrown-shot-launched vertically up
    - Problem on a projectile moving vertically up and down
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower
    - Problem on a toy rocket launched vertically up from a tall platform

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Read them attentively and learn how to solve this type of problems once and for all.

            Start from the very first lesson in this list.

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The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".

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