x = -11; x = 3 Get 0 on the right of each x + 11 = 0; x - 3 = 0 Multiply the left sides together and set it equal to the right sides multiplied together: (x + 11)(x - 3) = 0 x² - 3x + 11x - 33 = 0 x² + 8x - 33 = 0 So a quadratic function which when set equal to zero has solutions -11 and 3 is this function f: f(x) = x² + 8x - 33 Edwin