SOLUTION: solve the quadratic equations by extarcting[sic] or by factoring method whichever is applicable.
1. x² = 25 (space) : x = (blank)
Algebra.Com
Question 1164078: solve the quadratic equations by extarcting[sic] or by factoring method whichever is applicable.
1. x² = 25 (space) : x = (blank) , x = (blank)
2. ( x + 1 ) ( x - 2 ) (space) : x = (blank) , x = (blank)
3. x² + 3x = 0 (space) : x = (blank) , x =(blank)
4. ( x - 4 )² (space) : x = (blank) , x =(blank)
5. ( x - 3 ) ( 2x - 5 ) (space) : x = (blank) , x =(blank)
Found 2 solutions by josgarithmetic, Alan3354:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
----------------------------------------
solve the quadratic equations by extarcting or by factoring method whichever is applicable.
1. x² = 25 (space) : x = (blank) , x = (blank)
2. ( x + 1 ) ( x - 2 ) (space) : x = (blank) , x = (blank)
3. x² + 3x = 0 (space) : x = (blank) , x =(blank)
4. ( x - 4 )² (space) : x = (blank) , x =(blank)
5. ( x - 3 ) ( 2x - 5 ) (space) : x = (blank) , x =(blank)
-----------------------------------------
?
?
Attempting only #4 the way you may mean it,
Already a factored EXPRESSION. It is not any equation.
Attempting #3, an actual equation,
Roots should be obvious.
Factoring, have ,
and roots seen are 0 and -3.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
solve the quadratic equations by extarcting [sic] or by factoring method whichever is applicable.
1. x² = 25 (space) : x = (blank) , x = (blank)
2. ( x + 1 ) ( x - 2 ) (space) : x = (blank) , x = (blank)
3. x² + 3x = 0 (space) : x = (blank) , x =(blank)
4. ( x - 4 )² (space) : x = (blank) , x =(blank)
5. ( x - 3 ) ( 2x - 5 ) (space) : x = (blank) , x =(blank)
===============================
The quadratic equation method is always applicable.
-------
(space) and "x = (blank)" are not needed, and are just irritating.
----------------
#1 and #3 are equations, each has an equal sign.
The others are not equations.
RELATED QUESTIONS
Hello. Here are three problems involving the Quadratic Equation that I am having trouble (answered by ramkikk66)
solve the following quadratic equations by factoring or by any other techniques... (answered by stanbon)
Solve the following quadratic equations by factoring or by any of the techniques.... (answered by Nate)
Solve the following quadratic equations by factoring or by any of the techniques
x^2... (answered by checkley71)
Solve these quadratic equations by factoring.
4x2-25=0
-9x2+12x-4=0... (answered by checkley77)
Solve system by substitution or addition, whichever is easier.
2y - x = 3
x = 3y -... (answered by algebrapro18)
Hi, I need help with the following:
1. Solve by using substitution method.... (answered by checkley71)
Solve the following quadratic equations by factoring or by any other techniques of this... (answered by jim_thompson5910,Earlsdon)
solve the quadatric equations by factoring... (answered by stanbon)