SOLUTION: The length of a rectangle is 9 inches more than twice the width. If the area is to be at least 45 square inches, what are the possibilities for the width?

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Question 1160435: The length of a rectangle is 9 inches more than twice the width. If the area is to be at least 45 square inches, what are the possibilities for the width?
Answer by greenestamps(13215)   (Show Source): You can put this solution on YOUR website!


Let w be the width; then the length is 2w+9.

The area (length times width) is greater than or equal to 45 square inches:




or

Clearly the negative solution makes no sense in the problem. So

ANSWER: The width can be anything 3 inches or greater

NOTE: That result can be obtained in a few seconds with a bit of trial and error and simple arithmetic....


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