SOLUTION: The length of a rectangle is 9 inches more than twice the width. If the area is to be at least 45 square inches, what are the possibilities for the width?
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Question 1160435: The length of a rectangle is 9 inches more than twice the width. If the area is to be at least 45 square inches, what are the possibilities for the width?
Answer by greenestamps(13215) (Show Source): You can put this solution on YOUR website!
Let w be the width; then the length is 2w+9.
The area (length times width) is greater than or equal to 45 square inches:
or
Clearly the negative solution makes no sense in the problem. So
ANSWER: The width can be anything 3 inches or greater
NOTE: That result can be obtained in a few seconds with a bit of trial and error and simple arithmetic....
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