SOLUTION: x^2-x-13=0
Algebra.Com
Question 115710This question is from textbook
: x^2-x-13=0
This question is from textbook
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let's use the quadratic formula to solve for x:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve ( notice , , and )
Plug in a=1, b=-1, and c=-13
Negate -1 to get 1
Square -1 to get 1 (note: remember when you square -1, you must square the negative as well. This is because .)
Multiply to get
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
Multiply 2 and 1 to get 2
So now the expression breaks down into two parts
or
Now break up the fraction
or
Simplify
or
So these expressions approximate to
or
So our solutions are:
or
Notice when we graph , we get:
when we use the root finder feature on a calculator, we find that and .So this verifies our answer
RELATED QUESTIONS
x^2-2x-13=0 (answered by drj)
x^2-6x+13=0 (answered by jim_thompson5910)
x^2-2x-13=0 (answered by vheroli)
{{{ x^2 -2/sqrt( 13 )x + sqrt(13 ) = 0... (answered by solver91311)
1-13/x+36/x^2=0 (answered by jim_thompson5910)
solve x^2 - 2x - 13 =... (answered by Stitch,checkley77)
solve by factoring... (answered by Fombitz)
{{{2x^2-(4÷sqrt (13)) x+2sqrt (13)... (answered by josgarithmetic)
Solve by completing the square:... (answered by Earlsdon)