SOLUTION: One leg of a right triangle is 44 inches more than twicetwice the length of the other leg. The hypotenuse is 5 inches more than the shorter leg. Find the lengths of all

Question 1156595: One leg of a right triangle is
44
inches more than
twicetwice
the length of the other leg. The hypotenuse is
5
inches more than the shorter leg. Find the lengths of all the sides.
Found 3 solutions by MathLover1, Alan3354, josgarithmetic:
Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!

are you sure that
one leg is 44 inches more than twice the length of the other leg and the hypotenuse is 5 inches more than the shorter leg?????/////
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
One leg of a right triangle is
44
inches more than
twicetwice
the length of the other leg. The hypotenuse is
5
inches more than the shorter leg. Find the lengths of all the sides.
=============================
Makes the hypotenuse shorter than at least 1 of the legs.
Not possible.
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Assuming the 4 was doubled in entering by mistake,
leg, 2x+4
short leg, x
hypotenuse, x+5

Pythagorean Theorem:
.
.

Using general solution formula and accepting only positive value,
, the short leg.
NOW recheck if this makes any sense. Look again at the original expressions from the problem description. Can you have ? Does this match with the "solved" value for x?

-
to three sig figrs.
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