SOLUTION: A mortar shell is s feet above the ground after t seconds, where
f(t) = −16t2 + 512t + 64.
Find the height of the shell 26 seconds after it is fired.
The shell will have a h
Algebra.Com
Question 1156109: A mortar shell is s feet above the ground after t seconds, where
f(t) = −16t2 + 512t + 64.
Find the height of the shell 26 seconds after it is fired.
The shell will have a height of?
Answer by ikleyn(52780) (Show Source): You can put this solution on YOUR website!
.
Substitute the value t = 26 into the formula and calculate.
You can do it as easy, as I can, and you do not need my help for such a routine task.
RELATED QUESTIONS
A mortar shell is s feet above the ground after t seconds, where s = f(t) = -16t2 + 512t... (answered by Alan3354)
A mortar shell is s feet above the ground after t seconds, where s = f(t) = -16t^2 + 512t (answered by richwmiller)
The polynomial - 16t2 + 120t gives the height, in feet, reached by a fireworks shell in t (answered by richard1234)
The height in feet of a fireworks shell can be modeled h(t) = -16t2+224t , where t is the (answered by solver91311)
At a fireworks stand show, a 3 in shell is shot from a mortar at an angle of 75 degree.... (answered by Glaviolette)
when a 10-in. shell is shot from a mortar at an angle of 75 degrees, the height, y (in... (answered by Alan3354)
A fireworks shell is shot straight up with an initial velocity of 80 feet per second. Its (answered by lwsshak3,Alan3354,stanbon)
Suppose that an object is projected in such a way that its height above the ground in... (answered by Fombitz)
a bullet shot straight up is s feet above the ground in t seconds
[[[[where... (answered by checkley75)