SOLUTION: A model rocket is launched with an initial velocity of 170 ft/s. The height, h, of the rocket t seconds after launch is given by
h = −16t2 + 170t
. How many seconds after the
Question 1154815: A model rocket is launched with an initial velocity of 170 ft/s. The height, h, of the rocket t seconds after launch is given by
h = −16t2 + 170t
. How many seconds after the launch will the rocket be 314 ft above the ground? Round to the nearest hundredth. Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website! .
To get the answer, solve the quadratic equation
-16t^2 + 170t = 314.
You will get 2 roots.
One root is the solution for the model moving up, while the other root is the solution for the model falling down.