SOLUTION: The length of a rectangle is 7cm less than twice the width. Find the perimeter of the rectangle if it’s area is 72cm squared

Question 1152916: The length of a rectangle is 7cm less than twice the width. Find the perimeter of the rectangle if it’s area is 72cm squared
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Length,
Width,
Question asks for , perimeter.

Solve for w in .
.
.
.
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.

            MENTAL SOLUTION

The equation is w*(2w-7) = 72. Multiply both sides by 2 2w*(2w-7) = 144. Find two integer numbers, whose product is 144 and the difference is 7. In 6 seconds, you will find 2w = 16, 2w-7 = 9 (16*9 = 144). So, the answer is: the width = 16/2 = 8; the length = 2*8-7 = 9; the perimeter = 2*(8+9) = 2*17 = 34.

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