Maricopa's Success scholarship fund receives a gift of $110000. The money is invested in stocks, bonds, and CDs. CDs pay 4.25 % interest, bonds pay 2.6 % interest, and stocks pay 7.4 % interest. Maricopa Success invests $50000 more in bonds than in CDs. If the annual income from the investments is $4150, how much was invested in each account?
It'll take forever to solve this if you use the other person's method. Creating 6 equations with 6 variables is DEFINITELY too, too much, and when it's that COMPLICATED,
it's very likely you'll make some SERIOUS errors, and you may never get the correct answers. Plus, that's TOO, TOO RIDICULOUS! When you do that, a problem like this would
likely take up the entire time in a test, if it should ever appear on one.
Anyway, let the amount invested in CDs be C
Then amount invested in bonds = C + 50,000
So, amount invested in stocks = 110,000 - C - (C + 50,000) = 110,000 - C - C - 50,000 = 60,000 - 2C
We then get a SOLE (1) INTEREST INCOME equation: .074(60,000 - 2C) + .026(C + 50,000) + .0425C = 4,150
4,440 - .148C + .026C + 1,300 + .0425C = 4,150
.026C + .0425C - .148C = 4,150 - 4,440 - 1,300
+ .0260C - 4,440
+ .0425C - 1,300
+ .0685C SUB-TOTAL - 5,740
- .1480C + 4,150
- .0795C TOTAL - 1,590
We now have: - .0795C = - 1,590
C, or
That's IT!! A whole lot less COMPLEX!!
YOU can do the check!!
Out of curiosity, I'd love to see how the other person would complete this problem! No wonder he ran out of time.
Or, maybe it just got too intense and BORING for him, and he RAN! Who knows!!