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(a) Function P(d) = - 80d^2 + 960d - 2280 is a quadratic function of the argument (variable) "d".
For any quadratic function f(x) = ax^2 + bx + c with negative leading coefficient "a" at x^2,
its maximum is achieved at the value of = .
In your case, a= -80, b= 960. Therefore
= = = 6.
Thus the optimum price is 6 dollars (or whatever monetary units) per cartoon.
It provides the maximum profit of P(6) = -80*6^2 + 960*6 -2280 = 600 thousands of your monetary units.
(b) Make a plot on your own. // When a "student" asks me to make a plot, I always think that it is his (or her) job - not my.
(c) To answer this question, solve this quadratic equation
P(d) = 0, or -80*d^2 + 960*d -2280 = 0.
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On finding the maximum/minimum of a quadratic function see the lessons in this site
- HOW TO complete the square to find the minimum/maximum of a quadratic function
- Briefly on finding the minimum/maximum of a quadratic function
- HOW TO complete the square to find the vertex of a parabola
- Briefly on finding the vertex of a parabola
- A rectangle with a given perimeter which has the maximal area is a square
- OVERVIEW of lessons on finding the maximum/minimum of a quadratic function
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook under the topic "Finding minimum/maximum of quadratic functions".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.