SOLUTION: hey, could u please solve this equation. find the quadratic relation in vertex form that has zeros -3 and 5 and passes through (3,6). i found x-value which is the axis of sym

Question 113917: hey,
could u please solve this equation.
find the quadratic relation in vertex form that has zeros -3 and 5 and passes through (3,6).
i found x-value which is the axis of symmetry -3+5= 2/2 = 1
Therefore x=1
but i could not find the y-value
Please could u sovle it and send me back.
i will be waithing,
thank you,

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Since the zeros are and we can find the factorization using these zeros. We simply need to use the zero product property in reverse

or Start with the given solutions

or Get the numbers to the left side

Since either piece equals zero, then their product equals zero

However, this equation may not pass through (3,6). So let's introduce an "a" coefficient in front to get the equation:

Now since the equation passes through (3,6), this means x=3 and y=6

Plug in x=3 and y=6

Combine like terms

Multiply

Divide both sides by -12

Reduce

So our answer is which means the equation is

Notice if we graph and plot the point (3,6), we can see that the point lies on the line and has zeros -3 and 5. So this verifies our answer.

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